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3 years ago

write 6.847 in word form is the answer 6 + 0.8 + 0.04 + 0.007 or do they want six and eight hundred and 47 thousandths?

Mathematics

1 answer:

Alex787 [66]3 years ago

4 0

Answer:

six and eight hundred fourty-seven thousandths

Step-by-step explanation:

6 + 0.8 + 0.04 + 0.007 is called extended form, six and eight hundred fourty-seven thousandths is called word form.

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<img src="https://tex.z-dn.net/?f=%28%20%5Cfrac%7B1%7D%7B2%7D%20%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%20%5Cfrac%7B1%7D%7B2%7D%20ab

Zigmanuir [339]

Answer:

$\frac{1}{2}$ (a + 2b)(a - b)

Step-by-step explanation:

Assuming you require the expression to be factored

Given

$\frac{1}{2}$ a² + $\frac{1}{2}$ ab - b² ← factor out $\frac{1}{2}$ from each term

= $\frac{1}{2}$ (a² + ab - 2b²) ← factor the quadratic

Consider the factors of the coefficient of the b² term(- 2) which sum to give the coefficient of the ab- term (+ 1)

The factors are + 2 and - 1, since

2 × - 1 = - 2 and 2 - 1 = + 1, thus

a² + ab - 2b² = (a + 2b)(a - b) and

$\frac{1}{2}$ a² + $\frac{1}{2}$ ab - b² = $\frac{1}{2}$ (a + 2b)(a - b)

5 0

3 years ago

Use the graphing calculator to

Leviafan [203]

Answer:

Step-by-step explanation:

Answer is C: x-min = 0, x-max= 30, y-min = 0, y-max = 30

5 0

3 years ago

Read 2 more answers

A chain has a ribbon tied to it every 2/3 foot. If the chain is 10 2/3 feet long, how many ribbons are tied to the chain??

patriot [66]

Answer:

16 ribbons

Step-by-step explanation:

Given the length of the chain as 10 $\frac{2}{3}$ and there is a ribbon tied to it every $\frac{2}{3}$ , we can take the total length of the chain and divide by the measure of $\frac{2}{3}$ :

$10\frac{2}{3}=\frac{32}{3}$

$\frac{\frac{32}{3}}{\frac{2}{3}}=\frac{32}{3}*\frac{3}{2}=\frac{96}{6}=16$

When dividing with fractions, we use the rule of 'keep/change/flip' to keep the first fractions, change the operation to multiplication and flip the second fraction.

7 0

2 years ago

There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an

vesna_86 [32]

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

$C =100 -50\\C= 50\ students$

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

$D =110 -50\\C= 60\ students$