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WITCHER [35]
3 years ago
6

Find the values of x and y.

Mathematics
1 answer:
Doss [256]3 years ago
6 0

Answer: y=37.5degrees and x=110degrees

Step-by-step explanation: sum of angle in a quadrilateral =360 and opposite angles=180. 115+2y=180,2y=180-115=75. 2y/2=75/2. therefore y=37.5. while x=70+x=180,x=180-70=110. x=110

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What are the solutions of -1 ≤ x – 3 < 4
cricket20 [7]

Answer:

2 ≤ x  < 7

Step-by-step explanation:

-1 ≤ x – 3 < 4

Add 3 to each side

-1+3 ≤ x – 3+3 < 4+3

2 ≤ x  < 7

7 0
3 years ago
A number increased by 8 gives the same result as a number multiplied by 8. whay is that number?
Airida [17]
x+8=8x\\&#10;7x=8\\&#10;x=\frac{8}{7}
5 0
3 years ago
Please helppppppppppppppppppppppppppo
Delvig [45]

Answer:

The correct answer is choice D.

Step-by-step explanation:

Since the parabola opens sideways, that means the function will feature y^2 and not x^2, so you can immediately rule out options B and C. Because the graph also opens right, that means the coefficient of y^2 is positive. Using all of this information, you'll find that the correct answer is D: x = \frac{1}{12} y^2.

3 0
2 years ago
A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe
dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that n = 8

Each student has a 95% chance of passing their class independent of the other students, which means that p = 0.95

This probability is P(X = 8). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that n = 2

0.6634 probability all students pass in a class, which means that p = 0.6634.

This probability is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0
3 years ago
25. Find the sum of (8p2-2p + 15) and (11 – 2p2 – 1).
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<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

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