Let one acute angle be X and one be Y
X+Y=90 -------Eq.1
2X+12=Y
2X-Y=-12------Eq.2
solving eq 1&2 we get,
3x=78
∴X=26
substituting value X in equation.1
X+Y=90
Y=90-26
∴Y=64
⇒answer:- X=26°
Y=64°
Answer:
80,00
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,

Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.


So the Maximum area we are able to create with 800 ft of fencing is 80,00
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Googl may help. My cat is asleep am im too tired to solve too