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2 years ago

Whats the equation of this horizantal line

Mathematics

1 answer:

Klio2033 [76]2 years ago

4 0

Answer:

$y=-7$

Step-by-step explanation:

Hope this helps you.

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Andrew is building a scale model of an elephant. He determines that a real elephant is 10 feet tall and 14 feet long. If Andrew

Deffense [45]

<h3>Answer: 11.2 inches</h3>

Work Shown:

(real height)/(scale height) = (real length)/(scale length)

(10 feet)/(8 inches) = (14 feet)/(x inches)

10/8 = 14/x

10x = 8*14

10x = 112

x = 112/10

x = 11.2 inches

8 0

2 years ago

4. Which equation shows a proportional relationship?

Bas_tet [7]

Answer:

Step-by-step explanation:

8 0

3 years ago

An artist is hired to create an art display for the interior of a city building. The display is to span a total width of 10 yd .

lesya692 [45]

Answer:

8 portraits are going to be used in the display.

Step-by-step explanation:

This problem can be solved as a rule of three problem.

Each yd has 36 inches.

The display is to span a total width of 10 yd. So it is a total width of 360 inches.

Each portrait has a width of 45 in. How many portraits can there be?

1 portrait - 45 in

x portraits - 360 in

$45x = 360$

$x = 8$

8 portraits are going to be used in the display.

7 0

3 years ago

Can you use the product of powers property to simplify?<br> ANSWER ASAP PLEASE!!!!

slavikrds [6]

Ye, np.

5^2 * 6^4= 25*1296=32400

3 0

3 years ago

At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given <span>the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the </span><span>paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:
</span>
$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point <span>on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>.

4 0

3 years ago