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SIZIF [17.4K]
3 years ago
5

The segment show below form a triangle True or false?

Mathematics
1 answer:
seropon [69]3 years ago
5 0

Answer:

true

Step-by-step explanation:

because it would be

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WILL GIVE BRANLIEST TO WHOEVER ANSWERS CORRECTLY. Find quadratic equation for the x-intercepts of (6,0) and (26,0)
masya89 [10]
Use desmos!!! It’ll help and show you a graph!!
5 0
3 years ago
2 ways to decompose the number 749
kolezko [41]
Okay. You can decompose 749 with these ways:
700 + 40 + 9
or
500 + 200 + 40 + 9
6 0
3 years ago
Need help with 9 please
Debora [2.8K]

Answer:

x = 5

y = 1

Step-by-step explanation:

So move 2y from the second equation to the other side of the equals sign

2x +3y = 13

x = 3 + 2y

From here substitute X into the first equation

2(3 + 2y) + 3y = 13

Distribute

6 + 4y +3y = 13

Combine like terms and solve for y

7y = 7

y = 1

insert result into the original equation.

x-2(1) = 3

x - 2 = 3

x = 5

insert into other equation to check work

2(5) + 3(1) = 13

10 + 3 = 13 correct

6 0
3 years ago
Find the equivalent expression of 3+2(2p+4t)
NISA [10]

Remember to follow PEMDAS, and to only combine terms with like variables.

First, distribute the 2 to all terms within the parenthesis:

2(2p + 4t) = 2(2p) + 2(4t) = 4p + 8t

3 + 4p + 8t, or (D), is your answer choice, for it cannot be simplified anymore.

~

7 0
3 years ago
a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F
slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

               M= (c^2)/8 which is intern equal to 2\sqrt{2}

Step-by-step explanation:

           Find the area, by setting the limits as

               = 4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}4d\theta

                 =8\pi

Therefore;

Mxy=  \int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta

       z-bar = 8/3

M= 8\pi dividing it into two volume gives us = 4\pi

means  4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta

             4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)

              c=2\sqrt{2}

       

                 

                 

5 0
3 years ago
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