Using the method of Lagrange multipliers, we have the Lagrangian

with partial derivatives (set equal to 0)





From

and

, we find that

. Then substituting into

, we find

and substituting these into

, we get

So we have two possible critical points,

, which give extreme values of

and

, respectively.
If youre trying to solve for the variables you have to solve for one of them in one equation first, so if you solved for x in 2x+3y=16 youd get x=8-(3/2)y. Then youd have to sub in that x for the x in the other equation so youd get 3(8-(3/2)y)-2y=13 then solve for y. Once you have the value of y it should be the same in both equations. Plug that new value of y into the equation of youre choosing then sove for x
Since the function and choices are already given, the simplest method would be to try out the given values of x and see if the value of y obtained and given int he choices would coincide. Using this trial and error method, it has been shown that the correct answer among the choices is choice C, with the solution shown below:
y = -0.296x^2 + 2.7x
Using (4.6, 6.2):
y = -0.296(4.6)^2 + 2.7(4.6)
y = 6.2
Answer:
there is the answers❤ sorry its a little blurry
j>= -44
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