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3 years ago

Consider the following polynomial expression

Mathematics

1 answer:

zavuch27 [327]3 years ago

5 0

Step-by-step explanation:

a.13x8+4x5-16x2

b.8

c.3

d.13x8

e.16

They are required answer but,may be wrong.

hope it helps u and keep smiling ;)

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A foam toy is 2 inches wide. It doubles in size for every minute it is in water. Write an expression for the width of the toy af

Solnce55 [7]

it would be 2(2^5), which is two times two to the fifth power. you take the original size and double it for every minute, which is like squaring it, but to the power of five, because it doubles once every minute for five minutes. i hope this makes sense!:)

7 0

4 years ago

On Monday, there was no snow on the ground in Buffalo, New York. On Tuesday, three inches of snow fell.On Wensday a half an inch

mario62 [17]

Hi there!

Monday- 0 in.

Tuesday- 3 in.

Wedsnday- 2 1/2 in.

Thursday- 5 in.

Friday- 3 1/2 in.

Therefore, the answer is - 3 1/2 inches of snow was left on Friday.

Hope this helps you!

~DL

7 0

3 years ago

Solve. -7x=x^2+12 help

Nat2105 [25]

Hey There!

The answer to your problem is $x=-3$ or $x=-4$ both answers are correct!

Step 1: Subtract x²+12 from both sides.

−7x−(x²+12)=x²+12−(x²+12)

−x²−7x−12=0

Step 2: Factor left side of equation.

$(-x-3)(x+4)=0$

Step 3: Set factors equal to 0.

$-x-3=0$ or $x+4=0$

Get your answer:

$x=-3$ or $x=-4$

3 0

3 years ago

5. Nobu ate of one pizza, Brandi ate half

iren2701 [21]

Answer:

Step-by-step explanation:

Is a bien de su coma

7 0

3 years ago

Read 2 more answers

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

Zepler [3.9K]

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

3 0

4 years ago