Answer:

Step-by-step explanation:
Assuming that the first exponent in the formula for the curve should be 3, not 2...

The derivative is

The slope of the tangent line at the point (-1, 2) is the value of the derivative at x = -1.

The slope of the normal line is the opposite reciprocal of the slope of the tangent line.

Using the Point-Slope form of a linear equation, the normal line is

(12ab)(3t) = (12 · 3)(abt) = 36abt
Answer:
the answer is 12x +3
Step-by-step explanation:

so the slope of that line above is really -4/3, now
