3 years ago

Hi, Please Help Me With This Math Question! 8th Grade!

Mathematics

1 answer:

TEA [102]3 years ago

3 0

The answer for the question is 20.25

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Which special version of the Pythagorean Theorem can you use to find the length of any squares diagonal, d, using only the lengt

EleoNora [17]

The square's diagonal is the triangle's hypotenuse.

The Pythagorean theorem is = $a^{2}+b^{2}=c^{2}$

Here, 'c' is the hypotenuse and 'a' and 'b' are the two sides of the triangle.

As the side is given 12 inches, so this becomes

$12^{2}+12^{2}=d^{2}$

$144+144=d^{2}$

$d^{2}=288$

$d=\sqrt{288}$

$d=16.97$ inches

6 0

3 years ago

For each value of y, determine whether it is a solution to 12 = 2y +8.<br> Is it a solution

grin007 [14]

Answer: 2(0) + 8 does not equal 12, not a solution.

2(2) +8 = 12 yes it is a solution

2(-3) + 8 does not equal 12, not a solution

2(5) + 8 does not equal 12, not a solution.

Step-by-step explanation:

Looks like you need to plug in each y value given and multiplied by 2 and add 8

2(0) + 8 does not equal 12, not a solution.

2(2) +8 = 12 yes it is a solution

2(-3) + 8 does not equal 12, not a solution

2(5) + 8 does not equal 12, not a solution.

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3 years ago

Help plzzzz I need help ASAP thank you

pentagon [3]

Answer:

Step-by-step explanation:

3 0

2 years ago

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Evaluate this expression <br><br> <img src="https://tex.z-dn.net/?f=8%5E%7B-2%7D" id="TexFormula1" title="8^{-2}" alt="8^{-2}" a

shepuryov [24]

Answer:

0.015625

Step-by-step explanation:

Rule: $a^{-n} = \dfrac{1}{a^n}$

$8^{-2} = \dfrac{1}{8^2} = \dfrac{1}{64} = 0.015625$

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2 years ago

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Heyy can you please help me posted picture of question

True [87]

$\bigg( \frac{4}{5} \bigg)^6 = \dfrac{4^6}{5^6}$

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3 years ago

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