12n^2+12n+9=0 Please solve!

Mathematics

1 answer:

Bogdan [553]3 years ago

5 0

Answer:

n = (1/2)(-1 ± i√2)

Step-by-step explanation:

Among the several ways in which quadratic equations can be solved is the quadratic formula. Putting to use the coefficients {12, 12, 9}, we obtain the discriminant, b^2 - 4ac: 12^2 - 4(12)(9) = 144 - 432 = -288. The negative sign of this discriminant tells us that the quadratic has two unequal, complex roots. These roots are:

-b ± √(discriminant)

n = ---------------------------------

Here we have:

-12 ± √(-288) -12 ± i√2√144 -12 ± i12√2

n = ---------------------- = ------------------------ = --------------------

2(12) 24 24

or:

n = (1/2)(-1 ± i√2)

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