2 3/3 ÷ 3 Help!!!! I cant solve this in not good at maths

Mathematics

2 answers:

marta [7]3 years ago

8 0

Answer:

Step-by-step explanation:

amid [387]3 years ago

6 0

Answer:

Step-by-step explanation:

2 3/3 can be simplified to 3

3 / 3 is 1

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Tju [1.3M]

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3 years ago

What is sin θ when sec θ = square root of 5? Rationalize the denominator if necessary.

alexandr1967 [171]

$\bf sec(\theta )=\sqrt{5}\implies \cfrac{1}{cos(\theta )}=\sqrt{5}\implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{5}}}=cos(\theta )~\hfill \leftarrow \stackrel{\textit{let's find the}}{\textit{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}$

$\bf \pm\sqrt{(\sqrt{5})^2-1^2}=b\implies \pm\sqrt{5-1}=b\implies \pm\sqrt{4}=b\implies \pm 2=b \\\\[-0.35em] ~\dotfill\\\\ sin(\theta )=\pm\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{\sqrt{5}}}\implies \stackrel{\textit{rationalizing the denominator}}{\pm\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \pm\cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \pm\cfrac{2\sqrt{5}}{5}}$