Answer:
Every day, there is a 49% percent the locust population.
Step-by-step explanation:
To find the daily percent change of the locust population, we just need to find N(t) for t = 0, N(t) for t = 1, then subtract the second by the first, and then divide the result by the first:
N(t) = 8950*(0.7)^2t
N(0) = 8950*(0.7)^0 = 8950*1 = 8950
N(1) = 8950*(0.7)^2 = 8950*0.49 = 4385.5
Change = N(1) - N(0) = 4564.5
Percent change = Change/N(0) = 4564.5/8950 = 0.51 = 51%
As after one day, the population decrease by 51% of the inicial population, the remaining population is 100% - 51% = 49%, so we can write:
Every day, there is a 49% percent of the locust population.
To solve this problem you must apply the proccedure shown below:
1- You have that the laddder makes an angle of 
with the ground and the top of the ladder reaches 
.
2- Therefore, you have:
Where:
3-You must substitute values and solve for the lenght, as following:
Therefore, the answer is: 
Step-by-step explanation:
step 1. m: m is the variable, 1 is the coefficient, 1 is the degree, constant is 0.
step 2. 3t^2 +4t - 6: t is the variable, 3 and 4 are the coefficients, 2 is the degree, -6 is the constant.
step 3. 2 - h: h is the variable, -1 is the coefficient, 1 is the degree (highest variable exponent), the constant is 2.
step 4. -7a^2: a is the variable, -7 is the coefficient (before the variable), 2 is the degree, the constant is 0.
That would be 35%. if i’m right please mark me brainliest :)
