Answer:
Their are caculators online search the type of math it is then put caculator for example exponents caculator
Step-by-step explanation:
Answer:
10⁰×10¹-1¹⁰ < 10⁰×10¹×1¹⁰ < 10⁰+10¹×1¹⁰ < 10⁰+10¹+1¹⁰
Step-by-step explanation:
10⁰×10¹-1¹⁰ = 9
10⁰×10¹×1¹⁰ = 10
10⁰+10¹×1¹⁰ = 11
10⁰+10¹+1¹⁰ = 12
Answer:
a) Is it possible for Fred to accomplish this? Yes
b) If it is possible, what score does he need in his next game? 293
Step-by-step explanation:
Step 1
Let us represent the number of games Fred bowled to get an average of 177 = X
His total points scored in that game would be
177 × X
= 177X
To achieve an average of 178 for his next game,
The total number of points he scored was 199, hence that is represented as:
178 = 177X + 199/ X + 1
178(X + 1) = 177X + 199
178X + 178 = 177X + 199
178X - 177X = 199 - 178
X = 21
Hence, Fred bowled 21 games to achieve an average of 178
Therefore, the score he needs to have on the 23rd game is obtained as:
= (23 × 183) - (22 × 178) = 4209 - 3916 = 293
Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.
Answer:yeeyyh
Step-by-step explanation:
