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Vinvika [58]
3 years ago
9

A student is attempting to find a formula for the sequence below. Which statement best applies to the sample mathematical work?

Mathematics
2 answers:
monitta3 years ago
7 0
The sample is a geometri sequencethe ratio = -9 / 3 = -3= 27 / -9 = -3so it is clearly a geometric sequencethen the formula of a geometric sequence:
an = ar^(n-1)where an is the n terma is the initial termr is the rationn is the number of term
an = 3(-3)^(n-1)is the answer
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

Answer : B

Step-by-step explanation:

Our sequence is 3,-9,27,........This is a geometric sequence. whose first terms is 3 which is generally denoted by "a" .The common ratio is find out by taking the ration of second term to the first term. In this case it would be ,

r=\frac{-9}{3}

Hence r=-3  

Now the formula for the nth term of any geometric sequence is given as

a_{n} = ar^{n-1}

Hence we now replace the value of  a and r  in this to find the right answer which is

a_{n} = 3(-3)^{n-1}

Hence B option is correct as the first term is not taken into the account in this answer.

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What is the slope if you have (1,1) and (-3,-2)?
Serga [27]

Given two points (X1,Y1) and (X2,Y2) on a line, the slope =(Y2 - Y1) /(X2 - X1).

You are given the points (1,3) and (3,-2). Implying X1 =1 , Y1 =3, X2=3, Y2=-2

Use the formula for the slope above to answer the question. If you still have problems getting the correct answer, ask for more help.

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Read 2 more answers
Simplify the inequality:<br> -12.4x+8x &gt; -0.4x-5.2-2.7
ad-work [718]

Answer:

<h3><u>x < 1.975</u></h3>

Explanation:

-12.4x + 8x > -0.4x - 5.2 - 2.7

<em>Add similar elements: -12.4x + 8x = -4.4x</em>

-4.4x > -0.4x - 5.2 - 2.7

<em>Subtract -5.2 - 2.7: -7.9</em>

-4.4x > -0.4x - 7.9

<em>Multiply both sides by 10</em>

-4.4x · 10 > -0.4x - 7.9 · 10

<em>Refine</em>

-44x > -4x - 79

<em>Add 4x to both sides</em>

-44x + 4x > -4x - 79 + 4x

<em>Simplify</em>

-40x > -79

<em>Multiply both sides by -1 (Reverse the inequality)</em>

-40x (-1) > -79 (-1)

<em>Simplify</em>

40x < 79

Divide both sides by 40

40x / 40 < 79 / 40

<em>Simplify</em>

x < ⁷⁹⁄₄₀

<em>Turn the fraction into a decimal</em>

<h3><u>x < 1.975</u></h3>
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5 0
3 years ago
Compute the surface area of the portion of the sphere with center the origin and radius 4 that lies inside the cylinder x^2+y^2=
Tom [10]

Answer:

16π

Step-by-step explanation:

Given that:

The sphere of the radius = x^2 + y^2 +z^2 = 4^2

z^2 = 16 -x^2 -y^2

z = \sqrt{16-x^2-y^2}

The partial derivatives of Z_x = \dfrac{-2x}{2 \sqrt{16-x^2 -y^2}}

Z_x = \dfrac{-x}{\sqrt{16-x^2 -y^2}}

Similarly;

Z_y = \dfrac{-y}{\sqrt{16-x^2 -y^2}}

∴

dS = \sqrt{1 + Z_x^2 +Z_y^2} \ \ . dA

=\sqrt{1 + \dfrac{x^2}{16-x^2-y^2} + \dfrac{y^2}{16-x^2-y^2} }\ \ .dA

=\sqrt{ \dfrac{16}{16-x^2-y^2}  }\ \ .dA

=\dfrac{4}{\sqrt{ 16-x^2-y^2}  }\ \ .dA

Now; the region R = x² + y² = 12

Let;

x = rcosθ = x; x varies from 0 to 2π

y = rsinθ = y; y varies from 0 to \sqrt{12}

dA = rdrdθ

∴

The surface area S = \int \limits _R \int \ dS

=  \int \limits _R\int  \ \dfrac{4}{\sqrt{ 16-x^2 -y^2} } \ dA

= \int \limits^{2 \pi}_{0} } \int^{\sqrt{12}}_{0} \dfrac{4}{\sqrt{16-r^2}} \  \ rdrd \theta

= 2 \pi \int^{\sqrt{12}}_{0} \ \dfrac{4r}{\sqrt{16-r^2}}\ dr

= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}

= 8\pi ( - \sqrt{4} + \sqrt{16})

= 8π ( -2 + 4)

= 8π(2)

= 16π

4 0
2 years ago
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