A 3d cardboard box has 6 sides, each of which are rectangles. If you unfold the 3D box, and flatten it out, then you'll be left with 6 rectangles such as what you see in the attachment below. This is one way to unfold the box. This flattened drawing is the net of the 3D rectangular prism. You can think of it as wrapping paper that covers the exterior of the box. There are no gaps or overlapping portions. If you can find the area of each piece of the net, and add up those pieces, that gets you the total area of the net. This is the exactly the surface area of the box.
In the drawing below, I've marked the sides as: top, bottom, left, right, front, back. This way you can see how the 3D box unfolds and how the sides correspond to one another. Other net configurations are possible.
I'm assuming you want us to solve for the unknown variable z

Combine like terms on the right side

Use the distributive property on the left side

Add both sides by 20 to cancel out the "-20" on the left side

Divide both sides by 10

That is the value of the known variable, z, in this equation. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
isosceles trapezoid
Step-by-step explanation:
1) find the distance of the points

AB = 
BC = |7-4| = 3
CD = 
AD = |9-2| = 7
2) equation of the line that passes threw BC
y = 7
3) equation of the line that passes threw AD
y = 5
conclusion
the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid
Answer:
c
Step-by-step explanation: