Answer:
1.25 liters of oil
Step-by-step explanation:
Volume in Beaker A = 1 L
Volume of Oil in Beaker A = 1*0.3 = 0.3 L
Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L
Volume in Beaker B = 2 L
Volume of Oil in Beaker B = 2*0.4 = 0.8 L
Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L
If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

1.25 liters of oil are needed.
Answer:
(14-9i)+(2+3i) = 16-6i
Step-by-step explanation:
We need to find the equivalent of (14-9i)+(2+3i).
We need to add the two expressions.
(14-9i)+(2+3i) = 14+2 -9i+3i
= 16-6i
Here, the real part is 16
The imaginary part is -6
Hence, the required answer is equal to 16-6i.
Answer:
<h3>B.)Segment BC is proportional to segment EF, and angles A and D are congruent.</h3>
Step-by-step explanation:
If ΔABC and ΔDEF are similar, then
AB is proportional to DE
BC is proportional to EF
CA is proportional to FD
and
angles A and D are congruent
angles B and E are congruent
angles C and F are congruent
Step-by-step explanation:
the second one, they are in proportion to each other in respect to the interfere values