Simplify 8V 28
1 answer:
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y=∣x−1∣={
1−x
x−1
x<1
x≥1
}
Similarly y=3−∣x∣={
3+x
3−x
x<0
x≥0
}
The required region is a rectangle with length 2
2
and breadth
2
.
Hence, the area is 4. Hence, all the options are correct
Answer:
if you insert x and y values in equation you can find the exact equation