The area of figure ABCDEF can be computed as the sum of the areas of trapezoid ACDF and triangle ABC, less the area of trangle DEF.
trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
triangle ABC area = (1/2)(AC)(2) = 8
triangle DEF area = (1/2)(DF)(2) = 5
Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42
The actual area of ABCDEF is 42 square units.
Answer:
x=59deg
Step-by-step explanation:
We will use tangent to find the angle because we do not know the length of the hypotenuse.
Tan(x)=opp/adj
Tan(x)=30/18
Tan(x)~59
So the last option is correct. 59deg
Answer:
7.8
Step-by-step explanation:
First I will try 50. I got 127,550, so that was way too big.
Let me try a smaller number. How about 5. I got 155, so that was a bit too small.
Now I'll try 20. I got 8420. Looks like the number is between 5 and 20.
How about 7. I got 399.
Let me try 8. I got 584! That's really close. It's just a little too big.
I tried 7.5, and got 485.624. So close! Just a little higher.
Putting in 7.8 yields <u>543.192!</u> That's our answer.
Let us try and solve it analytically. We have that the side=x+3 together with the short side=s and the diagonal=x+4 satisfy the Pythagorean Theorem. Then we have that

. This yields

which yields s^2=2x+7, hence a) is the correct answer.