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Juli2301 [7.4K]
2 years ago
9

Ill give a brainliest if you can answer all three :))

Mathematics
2 answers:
Pavel [41]2 years ago
6 0

Answer:

4. A

8. D

9. B

Step-by-step explanation:

4. started with 10 points: +10

lost 20 points: -20

won 45 points: +45

10-20+45

8. 11-(-8)

=19

9. 100-(-50)-2

=150-2

=148

PLS GIVE BRAINLIEST

oee [108]2 years ago
5 0

Answer:

4 is A ; 8 is D ; 9 is B

Step-by-step explanation:

PLS GIMME BRAINLIEST

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An unfair die is twice as likely to roll an even number than an odd number. what is the probability of it rolling an odd number?
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The probability is always expressed as a part of the whole. So, it can be in terms of fraction or percentage. The numerator is the number of possible events while the denominator is the number of total events. Let x be the number of times you roll an odd number. So, the number of times you roll an even number would be 2x. The total rolls would then be x + 2x. Thus, the probability of rolling an odd number is

Probability = x/(2x + x) = x/3x = 1/3


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2 years ago
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nata0808 [166]
A pentagon and a abstract shape
8 0
2 years ago
A game decreased in price by 2/3. After the reduction it was priced at £13. What was the original price of the game?​
Archy [21]

Answer:

x = 39

Step-by-step explanation:

Based on the given conditions, write: x=\frac{13}{1-\frac{2}{3}}

Find common denominator and write numerators above common denominator: x=\frac{\frac{13}{3-2} }{3}

Calculate the sum or difference: x=\frac{\frac{13}{1} }{3}

Divide the fraction by multiplying its reciprocal: x=13*3

Calculate the product or quotient: x=39

Answer: x=39

5 0
2 years ago
Read 2 more answers
Help on this? thanks (:
Alex

Answer:

D

Step-by-step explanation:

24-6 = 18 32-6x3=18

Hope this helped!

4 0
3 years ago
Read 2 more answers
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
nalin [4]
First, you must know these formula  d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies  <span>dy/dx=cosx .e^(y+sinx), and then 
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of 
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that   d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
 finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is 
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
7 0
2 years ago
Read 2 more answers
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