X = -6 + y...so we sub in -6 + y for x in the other equation
x - 3y = 28
-6 + y - 3y = 28
-2y - 6 = 28
-2y = 28 + 6
-2y = 34
y = -34/2
y = - 17
x = -6 + y
x = -6 - 17
x = - 23
solution is (-23,-17)
Step-by-step explanation:
First, apply the distributive property to the left side of the equation. Multiply each of the two numbers inside the parentheses by 12 and then combine those products. Next, solve as you would solve any two-step equation. To isolate \begin{align*}12x\end{align*} on the left side of the equation, add 24 from both sides.
For the first question the answer would be the first quadrant
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The two non negative real numbers with a sum of 64 that have the largest possible product are; 32 and 32.
<h3>How do we solve the nonnegative real numbers?</h3>
Let the two numbers be x and y.
Thus, if their sum is 64, then we have;
x + y = 64
y = 64 - x
Their product will be;
P = xy
Putting (64 - x) for y in the product equation we have;
P = (64 - x)x
P = 64x - x²
Since the product is maximum, let us find the derivative;
P'(x) = 64 - 2x
At P'(x) = 0, we have;
64 - 2x = 0
2x = 64
x = 64/2
x = 32
Thus; y = 64 - 32
y = 32
Read more about nonnegative real numbers
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Answer:
ok
Step-by-step explanation:
what do u mean by the simplest form?