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aivan3 [116]
3 years ago
5

Pls help ASAP !!!!!!!!

Mathematics
1 answer:
Anastasy [175]3 years ago
7 0

Answer:

C I got that

shdjdhfbfhfkdnfhfhfhfbf it wants me to do 20 characters long

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Graph the system of inequalities. Then use your graph to identify the point that represents a solution to the system. x > 4 y
8_murik_8 [283]
The first thing you should do in that case is to graph both lines.
 Once graphed you must see which region of the Cartesian plane they meet their respective inequalities.
 The solution of the inequation system is the shaded region shown.
 The point sought is
 P = (5, -2)
 answer
<span> (5, –2)</span>

7 0
3 years ago
Adam and his dad share the cost of the meal in the ratio of 2:3.
lapo4ka [179]
52.20÷3= 17.40×5=87. The meal cost £87
6 0
4 years ago
Read 2 more answers
What must be true for lines a and b to be parallel lines? Check all that apply
iren [92.7K]

the question does not present the options, but this does not interfere with the resolution


we know that

if a and b are parallel lines

so


1) m∠2=58°------> by corresponding angles


2) m∠1=4x-10------> by alternate exterior angles


3) [m∠2+m∠(3x-1)]+m ∠1=180°------> by supplementary angles

58+(3x-1)+4x-10=180

7x=180-47

7x=133

x=19°


4) angle (4x-10)=-4*19-10-------> 66°


5) angle 3x-1=3*19-1-------> 56°

3 0
3 years ago
A 15 foot flagpole casts an 11 foot shadow. At the exact same time a 28 foot tree casts a shadow. Which proportion would correct
marishachu [46]
The longer an object, the longer the shadow they cast at a given time of the day and vice versa. This is called direct proportionality. At the same time,

If 15 foot flagpole ---- casts 11 foot shandow
    28 foot tree -------- casts ?? foot shadow

The proportion would therefore be:

Length of shadow cast by tree = (28/15)*11 = 20.533 foot.
8 0
3 years ago
What is one of the solutions to the following equations? y2+x2=53<br> Y-x=5
Olenka [21]
(1)  y² + x² = 53
(2)  y - x = 5 ⇒ y = x + 5

subtitute (2) to (1)

(x + 5)² + x² = 53      |use (a + b)² = a² + 2ab + b²

x² + 2x·5 + 5² + x² = 53

2x² + 10x + 25 = 53     |subtract 53 from both sides

2x² + 10x - 28 =0     |divide both sides by 2

x² + 5x - 14 = 0

x² - 2x+ 7x - 14 = 0

x(x - 2) + 7(x - 2) = 0

(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7

subtitute the values of y to (2)

for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3

Answer: x = 2 and y = 7 or x = -7 and y = 3
4 0
4 years ago
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