Question

Please help me thank you

Answer 1

Answer:

$x = 2\sqrt{5}$

Step-by-step explanation:

Given

The attached triangle

Required

Find x

Using the sin function

$sin(\theta) = \frac{Opposite}{Adjacent}$

$sin(30) = \frac{\sqrt{5}}{x}$

Make x the subject

$x = \frac{\sqrt{5}}{sin(30)}$

$x = \frac{\sqrt{5}}{1/2}$

Express as:

$x = \sqrt{5}/1/2}$

$x = \sqrt{5}*2/1$

$x = \sqrt{5}*2$

$x = 2\sqrt{5}$