Answer:
9.86 inches
Step-by-step explanation:
Given:
The cup will be a right circular cone with:-
Radius, r = 3 inches
Volume of cone = 93 cubic inches
Height of the cup, h = ?
Solution:
<u>By using :-</u>
<u />

By dividing both sides by 9.43

Thus, the cup need to be 9.86 inches taller to hold 93 cubic inches of water.
Answer:
310°
Step-by-step explanation:
The sum of arcs around a circle is 360°.
MPN +MN = 360°
MPN = 360° -MN . . . . . . . . subtract MN
MPN = 360° -50° = 310° . . . fill in the given value
The measure of major arc MPN is 310°.
Answer:
10 is your answer
Step-by-step explanation:
Note that the side given to us has a measurement of 5 for one of the legs of the isosceles.
This means that the <em>1</em> side on the 30-60-90 triangle has a measurement of 5.
Now, note the measurements of the triangle sides for a 30-60-90 triangle. They measure at: 1 , √3 , 2.
the side 1 is given to us, at 5. You are solving for the hypothenuse (2). Multiply 2 to the side 1
5 * 2 = 10
10 is your answer
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Answer:
Click on the screenshot, I labeled the parts
Hope this helps :))
Answer: :} where is the rest of the question
Step-by-step explanation: