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Rudik [331]
3 years ago
15

Round this number to the given place values:

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

Ones place: 456.3000

tenths place: 456.3000

hundredths place: 456.2990

thousandths place: 456.2991

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Holly checked her answer to a division problem by estimating the quotient. Which is the best estimation of the quotient?
Andre45 [30]
Answer: 4

Try just dividing 23/5 and you’d get 4 something. But since 5.97 is close to 6 you can also mentally divide 23/6 and get 3something (it’d be really close to 4)



5 0
3 years ago
Read 2 more answers
ALGEBRA 1 HELP!!!!<br> •GIVING BRAINLIEST
pickupchik [31]
Amount= Deposit or initial amount ( 1+ percent increase) ^period of time
So Amount= 50(1+0.1)^3
= 50(1.1)^3
= 50(1.331)
=66.55
So she will have $66.55 in 3 years.
4 0
3 years ago
Write the following as an equation. Amy is 16 yrs older than Peter, whose age is 'x' yrs. 6 yrs ago, her age was twice Peter's a
azamat
Amy's current age is 16 years greater than Peter's age, so Amy's current age is equal to x + 16.

6 years ago, Amy's age was equal to twice that of Peter's age at that point, so her age was 2(x - 6).

As currently her age is x + 16 then 6 years ago her age was x + 16 - 6, which is x + 10.

As 6 years ago her age was equal to 2(x - 6) and x  + 10, we can see that x + 10 = 2(x - 6).
5 0
3 years ago
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there in the c
Ivan

The total possibilities can be 756 ways.

<h3>What is combination?</h3>

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order. Combinations can be confused with permutations.

Given:

The number of ways in which we can select atleast 3 men in the committee are 756.

Number of men = 7

Number of women = 6

Number of people that should be selected in the committee = 5

Now,

N(M = 3) = 7C_3* 6C_2

=35*15

=525

N(M = 4) = 7C_4* 6C_1

=35*6

=210

N(M = 3) = 7C_5* 6C_0

=21*1

=21

So, total possibilities can be = 525 + 210 + 21 = 756 ways.

learn more about combination here:

brainly.com/question/28390900

#SPJ4

7 0
1 year ago
Solve the compound inequality. –1 &lt; 4m + 7 ≤ 11 A. −14
ankoles [38]
This is what I got :-(

4 0
2 years ago
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