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Aleks04 [339]
2 years ago
8

Which expression is equivalent to x 2 - 17x - 60?

Mathematics
2 answers:
m_a_m_a [10]2 years ago
8 0

Answer:

( x − 20)( x + 3)

Step-by-step explanation:

i did the test

creativ13 [48]2 years ago
6 0

Answer:

(x-20)(x+3)

Step-by-step explanation:

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Using the chart "Amount of $1 at Compound Interest" from previous reading section "More Compound Interest", find the total amoun
vitfil [10]

Answer:

Step-by-step explanation:

the formula used for any interest other then continuously is

A=P(1+r/n)^nt

so... r=rate in decimal form ONLY n=how often interest is paid t=time passed

A=3000(1+.08/1)^(1)(5) = annually

A=3000(1+.08/2)^(2)(5)

A=3000(1+.08/4)^(4)(5)

use you calculator to get the answer

it is good practice to use your calculator now because soon you will be using it for population questions and those need to be entered very carefully.

7 0
3 years ago
Please answer my question now in two minutes
Tresset [83]

Answer:

given,triangle EFG is congruent to triangle HIJ,THEIR corresponding sides are equal,

so, 10x=x+45

10x_x=45

or,9x=45

therefore , x=5

again,

3y = y+14

or, 3y_y=14

or, y=14/2

therefore the value of y is 7.

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hope its helpful to uh...

3 0
2 years ago
If 8 chairs cost $1,064 what is the cost of 11 chairs​
evablogger [386]
1463 (1064 divided by 8= 133, 133x11)
6 0
3 years ago
HELP!
Advocard [28]

9)its a fraction

x=−451/19

y=−302/19



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Line 1: y = 5x +13

Line 2: y = 5x + 12

7 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
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