Answer:



Step-by-step explanation:
= (probability of entire face value paid*face value+probability of entire face value not paid*percent of face value paid*face value)/(1+discount rate)^years to maturity
probability of entire face value paid = 75%
face value = 1000
probability of entire face value not paid = 25%
percent of face value paid= 60%
discount rate = 15%
years to maturity = 3



Answer:
Subtracting 7
Step-by-step explanation:
<u><em>Given:</em></u>
<em>Clara is stacking cups; she put 45 plastic cups in the first stack, 38 plastic cups in the second stack, 31 plastic cups in the third stack, and 24 plastic cups in the fourth stack. </em>
<u><em>To Find:</em></u>
<em>What kind of sequence is this?</em>
<u><em>Solve:</em></u>
<em>Let's make a table:</em>
<em />
<em>[1 stack] 45 </em>
<em>[2 stack] 38</em>
<em>[3 stack] 31</em>
<em>[4 stack] 24</em>
<em />
<em>Now all we have to do is subtract to see what each is:</em>
<em>45 - 38 = 7</em>
<em>38 - 31 = 7</em>
<em>31 - 24 = 7</em>
<em>Thus,</em>
<em>[1 stack] 45 ⇒ 7</em>
<em>[2 stack] 38 ⇒ 7 </em>
<em>[3 stack] 31 ⇒ 7 </em>
<em>[4 stack] 24 ⇒ 7 </em>
<em>Hence, each stack is going down by 7.</em>
<em />
<u><em>Kavinsky</em></u>
<em />
Answer:
Neither
Step-by-step explanation:
The slopes are not opposite and they are not equal either
line up 2x+3y=42 and -3x +2y=16
2x+3y=42=-3x+2y=16
get each term on one side and isolate.
If this is not possible, you have your answer. Another way to do this is graphing it and seeing if the two lines intersect, and if they do, if they make a right angle
Given.
Radius of the Half sphere is 3 inches.
From the figure;
Radius of half sphere= Radius of cylinder= Radius of cone=3inches
Height of cone= 4inches.
Height of cylinder=6inches.
Volume of cone=(πr²h)/3
=(π3²×4)/3
=(12π) inch³
volume of cylinder= πr²h=π3²6=54π inch³
Volume of half sphere= (4/3) π r³=π(4×3³)/3 (1/2)=π×4×9/2=18π inch³
Total area of Composite figure=(12π +54π +18π) inch³
=84π inch³
=(84)× 22/7inch³
=12×22 inch³
=264inch³
Hope it helps...
Regards;
Leukonov/Olegion.