Algorithm of the Nios II assembly program.
- Attain data for simulation from the SW11-0, on the DE2-115 Simulator
- The data will be read from the switches in loop.
- The decimal output is displayed using the seven-segment displays and done using the loop.
- The program is ended by the user operating the SW1 switch
and
The decimal equivalent on the seven-segment displays HEX3-0 is
- DE2-115
- DE2-115_SW11
- DE2-115_HEX3
- DE2-115_HEX4
- DE2-115_HEX5
- DE2-115_HEX6
- DE2-115_HEX7
<h3>The Algorithm and
decimal equivalent on the
seven-segment displays HEX3-0</h3>
Generally, the program will be written using a cpulator simulator in order to attain best result.
We are to
- Attain data for simulation from the SW11-0, on the DE2-115 Simulator
- The data will be read from the switches in loop.
- The decimal output is displayed using the seven-segment displays and done using the loop.
- The program is ended by the user operating the SW1 switch
This will be the Algorithm of the Nios II assembly program .
Hence, the decimal equivalent on the seven-segment displays HEX3-0 is
- DE2-115
- DE2-115_SW11
- DE2-115_HEX3
- DE2-115_HEX4
- DE2-115_HEX5
- DE2-115_HEX6
- DE2-115_HEX7
For more information on Algorithm
brainly.com/question/11623795
Answer:
a drawing, at relatively large scale, of a part of a building, machine, etc., with dimensions or other information for use in construction.
Explanation:
<h2>
Answer:</h2>
7532V
<h2>
Explanation:</h2>
For a given transformer, the ratio of the number of turns in its primary coil () to the number of turns in its secondary coil () is equal to the ratio of the input voltage () to the output voltage () of the transformer. i.e
= ----------------(i)
<em>From the question;</em>
= number of turns in the primary coil = 8 turns
= number of turns in the secondary coil = 515 turns
= input voltage = 117V
<em>Substitute these values into equation (i) as follows;</em>
=
<em>Solve for </em><em>;</em>
= 117 x 515 / 8
= 7532V
Therefore, the output voltage (in V) of the transformer is 7532
Answer:
The solution code is written in Java.
- double [] alpha = new double[50];
-
- for(int i =0; i < 25; i++){
- alpha[i] = i * i;
- }
-
- for(int j = 25; j < 50; j++){
- alpha[j] = j * 3;
- }
Explanation:
Firstly, the syntax to declare an array variable <em>alpha</em> of type double and initialize it with 50 components is presented in Line 1.
Next, use a for-loop to traverse through the first 25 components (Line 3). Use * operator to multiply index variable by itself (to square it) and assign it to the current component of the<em> alpha</em> array (Line 4).
Create another for-loop to traverse through the last 25 components (Line 7). This time, multiply the index variable with 3 and assign it to the current component of the <em>alpha</em> array (Line 8).
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