The giant outlier is Palm Beach county. We can see that it lies well beyond the range of votes this regression model would predi
1 answer:
Answer:
Hello your has some missing information attached below is the missing information
answer : 2355.62
Step-by-step explanation:
<u>Calculating the residual for Palm Beach county</u>
Given that total votes = 430772
and The regression equation = 56.115131 + 0.0023197 * Total Votes
The predicted Buchanan = 56.115131 + 0.0023197 * 430772 = 1055.377
while the Actual Votes Buchannan = 3411
Residual for Palm Beach county = Actual votes Buchannan - Predicted
= 3411 - 1055.377 = 2355.62
Note :
b0: 56.1132
b1: 0.0023
R2: 0.4593
The statistic that tests H0: ß1= 0: 7.43
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Answer:
Step-by-step explanation:
The first equation is
The second equation is
When we graph these two equations, <em>they will meet at a point which represent the solution of the two equations</em>.
We can solve the two equations simultaneously to determine their point of intersection.
Let us substitute the second equation into the first equation to get;
Multiply through by 2 to get;
Group similar terms to obtain;
Simplify;
Divide both sides by 3;
Put into the second equation;
Therefore the graphs of the two functions intersect at (2,3)
See graph in attachment.
Using a discrete probability distribution, it is found that:
a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
c) The expected value is of 1.3 lawns mowed on a randomly selected day.
<h3>What is the discrete probability distribution?</h3>Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:
- P(X = 0) = 0.2.
- P(X = 1) = 0.4.
- P(X = 2) = 0.3.
- P(X = 3) = 0.1.
Item a:
P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
Item b:
There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
Item c:
The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:
E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.
The expected value is of 1.3 lawns mowed on a randomly selected day.
More can be learned about discrete probability distributions at brainly.com/question/24855677