Answer:
C.
Step-by-step explanation:
So, if the new image coordinates are (7,9) and it is dilated from the origin there is a rule. If it is dilated from the origin you would multiply the pre-image coordinates by the scale factor so, (kx,ky) where k is the scale factor. In this case, we would divide by 2.5 so 7 divided by 2.5 is 2.8 and 9 divided by 2.5 is 3.6. The correct answer would be C. (2.8,3.6).
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Answer:
A
First prove Triangle ABC is congruent to Triangle CDA, and then state AD and BC are corresponding sides of the triangles.
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Answer: The area of Figure ABCDE is 79.5 square units.
Step-by-step explanation:
<em>Triangle ABC is the top triangle of Figure ABCDE.</em>
<u>Triangle ACD is the triangle on the right of Figure ABCDE.</u>
Triangle AED is the triangle on the bottom left of Figure ABCDE.
So, we need to add <em>23.85</em>, <u>29.4</u>, and 26.25 to get the area of Figure ABCDE!
23.85 + 29.4 + 26.25 = 79.5
Answer:

Step-by-step explanation:
Given function:

As per question statement:
Initial temperature of bottle is 70
.
i.e. when time = 0 minutes, f(t) = 70 

After t = 3, f(t) = 42

Hence, the value is:

Answer:
10
Step-by-step explanation:
8+5+15+12+10= 50 / 5 = 10