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3 years ago

10

for each metal that participated in a chemical change, right type of metal that is based on your examination of the periodic tab

le

1 answer:

CaHeK987 [17]3 years ago

3 0

I guess the answer <span>can be an alkali metal, alkaline earth metal, or transition metals.

Hope this helps :)

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What is the molarity of a solution in which 25.3 grams of potassium bromide is dissolved in 150. mL of solution?

irga5000 [103]

Answer:

~1.417M

Explanation:

Molarity=(number of moles of solute)/(litres of solution)

In this case, we need to find moles of potassium bromide.

Mass=25.3g

Molar mass= 119g/mol

moles=(mass/molar mass)

=(25.3)/(119)

=0.2126moles of potassium bromide

Molarity=(0.2126)/(150/1000)

~1.417M

Hope this helps:)

6 0

3 years ago

Read 2 more answers

Las sustancias ionicas y los metale sson electricamente neutros. ¿como es esto posible si estan formados por iones, que posen ca

Anton [14]

Answer:

ver explicacion

Explanation:

Los iones se forman cuando las especies químicas pierden o ganan electrones.

Las sustancias iónicas consisten en un ión positivo y negativo cuyas cargas se equilibran exactamente entre sí, por lo que el compuesto iónico es neutro.

Los átomos de metal se mantienen unidos por el enlace metálico. Esto implica la interacción entre iones metálicos cargados positivamente y un mar de electrones negativos. Las cargas positivas de los iones metálicos están exactamente equilibradas por el mar de electrones cargados negativamente, por lo que el metal es neutro.

8 0

3 years ago

How many formula units are there in 450 g of Na2S04?

Mashutka [201]

Formula units in 450 g of $Na_{2} So_{4}$ is 1.93 × 10²⁴ formula units.

<u>Explanation:</u>

First we have to find the number of moles in the given mass by dividing the mass by its molar mass as,

$$\frac{450 g}{142.04 g/mol} = 3.2 moles$

Now, we have to multiply the number of moles of Na₂SO₄ by the Avogadro's number, 6.022 × 10²³ formula units/mol, so we will get the number of formula units present in the given mass of the compound.

3.2 mol × 6.022 × 10²³ = 1.93 × 10²⁴ formula units.

So, 1.93 × 10²⁴ formula units is present in 450g of Na₂SO₄.

4 0

3 years ago

A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

$Molarity=\frac{moles}{\text{Volume of solution(L)}}$

Moles of glucose = $\frac{18.5 g}{180 g/mol}=0.1028 mol$

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = $\frac{0.1028 mol}{0.1 L}=1.028 mol/L$

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = $M_1=1.208 mol$

Volume of the solution taken = $V_1=30.0 mL$

Molarity of the solution after dilution = $M_2$

Volume of the solution after dilution= $V_2=0.500L = 500 mL$

$M_1V_1=M_2V_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}$

$M_2=0.07248 mol/L$

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

$0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}$

Moles of glucose = $0.07248 mol/L\times 0.1 L=0.007248 mol$

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0

4 years ago

On July 8th, I will be 8.51472x10^8 seconds old. How old will I be in years? (Assume 365 days in a year.) Group of answer choice

KatRina [158]

Answer:

26.98

almost 27 years

5 0

3 years ago