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Leya [2.2K]
3 years ago
15

Write the isotope notation for the following isotope: copper-63, copper-65, magnesium-24, magnesium-25, magnesium-26, lithium-6,

and lithium-7.
Chemistry
1 answer:
andrey2020 [161]3 years ago
3 0
63/29 Cu (copper-63)
65/29 Cu (copper-65)
24/12 Mg (magnesium 24)
25/12 Mg (magnesium 25)
26/12 Mg (magnesium 26)
6/3 Li (lithium 6)
7/3 Li (lithium 7)

The top number is the mass number and you find that by adding the number of neutrons and atomic number
The bottom number is the atomic number and it’s the number or protons
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1.6g of a compound were found to contain 0.64g of copper, 0.32g of sulfur and 0.64g of oxygen. Calculate it's empirical formula.
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The empirical formula of the compound containing 0.64 g of copper, 0.32 g of sulphur and 0.64 g of oxygen is CuSO₄

From the question given above, the following data were obtained:

Mass of Cu = 0.64 g

Mass S = 0.32 g

Mass of O = 0.64 g

<h3>Empirical formula =? </h3>

The empirical formula of the compound can be obtained as follow:

Cu = 0.64 g

S= 0.32 g

O = 0.64 g

Divide by their molar mass

Cu = 0.64 / 63.5 = 0.01

S= 0.32 / 32 = 0.01

O = 0.64 / 16 = 0.04

Divide by the smallest

Cu = 0.01 / 0.01 = 1

S= 0.01 / 0.01 = 1

O = 0.04 / 0.01 = 4

Therefore, the empirical formula of the compound is CuSO₄

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