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ANEK [815]
3 years ago
11

5

Chemistry
1 answer:
andriy [413]3 years ago
5 0

Answer:

reaction 1 and reaction 4 both are decomposition reactions

while reaction 2 is double displacement reaction and reaction 3 and 5 are combination reactions

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glucose 6‑phosphate+H2O⟶glucose+Pi glucose 6‑phosphate+H2O⟶glucose+Pi K′eq1=270 K′eq1=270 ATP+glucose⟶ADP+glucose 6‑phosphate AT
ddd [48]

Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

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For reaction,

1. K′eq1=270,

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= - 8.315 x 298 x ln 270

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2. K′eq2=890

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=  - 16.82 kj/mol

therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

Thus, -30.7 kj/mol is the correct answer.

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