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FrozenT [24]
3 years ago
7

Find the missing part.

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

y=\frac{15\sqrt{3}}{4}

Step-by-step explanation:

We are given that

\theta_1=60^{\circ}

\theta_2=30^{\circ}

We have to find the missing part.

\frac{x}{15}=cos\theta_1=cos60^{\circ}

Using the formula

\frac{base}{hypotenuse}=cos\theta

x=15cos60^{\circ}=\frac{15}{2}

\frac{z}{15}=sin60^{\circ}

Using the formula

\frac{Perpendicular\;arm}{hypotenuse}=sin\theta

z=15\times \frac{\sqrt{3}}{2}=\frac{15\sqrt{3}}{2}

Now,

\frac{a}{x}=cos60^{\circ}

\frac{a}{\frac{15}{2}}=\frac{1}{2}

a=\frac{1}{2}\times 15/2=\frac{15}{4}

y=x sin60^{\circ}

y=\frac{15}{2}\times \frac{\sqrt{3}}{2}

y=\frac{15\sqrt{3}}{4}

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