Question

Find the missing part.

Answer 1

Answer:

$y=\frac{15\sqrt{3}}{4}$

Step-by-step explanation:

We are given that

$\theta_1=60^{\circ}$

$\theta_2=30^{\circ}$

We have to find the missing part.

$\frac{x}{15}=cos\theta_1=cos60^{\circ}$

Using the formula

$\frac{base}{hypotenuse}=cos\theta$

$x=15cos60^{\circ}=\frac{15}{2}$

$\frac{z}{15}=sin60^{\circ}$

Using the formula

$\frac{Perpendicular\;arm}{hypotenuse}=sin\theta$

$z=15\times \frac{\sqrt{3}}{2}=\frac{15\sqrt{3}}{2}$

Now,

$\frac{a}{x}=cos60^{\circ}$

$\frac{a}{\frac{15}{2}}=\frac{1}{2}$

$a=\frac{1}{2}\times 15/2=\frac{15}{4}$

$y=x sin60^{\circ}$

$y=\frac{15}{2}\times \frac{\sqrt{3}}{2}$

$y=\frac{15\sqrt{3}}{4}$