Question

Prove that the product of any two consecutive natural numbers is even.

Answer 1

Answer with Step-by-step explanation:

Let us assume the 2 consecutive natural numbers are 'n' and 'n+1'

Thus the product of the 2 numbers is given by

$Product=n(n+1)$

We know that the sum of 'n' consecutive natural numbers starting from 1 is

$S_n=\frac{n(n+1)}{2}\\\\\therefore n(n+1)=2\times S_n............(i)$

Thus from equation 'i' we can write

$Product=2\times S_n$

As we know that any number multiplied by 2 is even thus we conclude that the product of 2 consecutive numbers is even.