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Serga [27]
3 years ago
13

What is the range and domain of: y= 4|x|-1

Mathematics
1 answer:
stich3 [128]3 years ago
5 0
Function: y = 4|x| - 1.


Domain: R (all real numbers).


Range: As we know, the absolute value of x is always a non-negative number:

|x| >= 0

4|x| >= 4 * 0

4|x| >= 0

4|x| - 1 >= -1

y >= -1 <----- this is the range


I hope this helps. =)

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On a recent day 8 euros were worth $9 and 24 euros were worth $27 write an equation of the form y equals kx to show the relation
attashe74 [19]

Answer:

y=8x/9

Step-by-step explanation:

Given that 8 euros were worth $9 and

24 euros were worth $27.

Let y represent the number of Euros and x no of dollars.

Given that the relation is of the form y = kx+C

When x=0 y =0,

i.e. C =0

Hence equation is of the form y = kx

Substitute x=8 and y =9

We get 9 = 8k

Or k =8/9

Hence relation is y=8x/9 is the relation between x and y.

WE can verify this for 27 dollars worth 24 euros.

24 =8/9(27) is true.

Thus equation is verified.


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3 years ago
Translate the following into algebraic form: The difference of forty-seven and a number
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
The CEO of a clothing company estimates that 52% of customers will make a purchase. Part A: How many customers should a salesper
4vir4ik [10]

Answer:

(a) The expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b) The probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

Step-by-step explanation:

Let<em> </em>the random variable <em>X</em> be defined as the number of customers the salesperson assists before a customer makes a purchase.

The probability that a customer makes a purchase is, <em>p</em> = 0.52.

The random variable <em>X</em> follows a Geometric distribution since it describes the distribution of the number of trials before the first success.

The probability mass function of <em>X</em> is:

P(X=x)=(1-p)^{x}p

The expected value of a Geometric distribution is:

E(X)=\frac{1-p}{p}

(a)

Compute the expected number of should a salesperson expect until she finds a customer that makes a purchase as follows:

E(X)=\frac{1-p}{p}

         =\frac{1-0.52}{0.52}\\=0.9231

This, the expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b)

Compute the probability that a salesperson helps 3 customers until she finds the first person to make a purchase as follows:

P(X=3)=(1-0.52)^{3}\times0.52\\=0.110592\times 0.52\\=0.05750784\\\approx 0.058

Thus, the probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

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Which conclusion can be drawn from the graph data?
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