To determine the centroid, we use the equations:
x⁻ =
1/A (∫ (x dA))
y⁻ = 1/A (∫ (y dA))
First, we evaluate the value of A and dA as follows:
A = ∫dA
A = ∫ydx
A = ∫3x^2 dx
A = 3x^3 / 3 from 0 to 4
A = x^3 from 0 to 4
A = 64
We use the equations for the centroid,
x⁻ = 1/A (∫ (x dA))
x⁻ = 1/64 (∫ (x (3x^2 dx)))
x⁻ = 1/64 (∫ (3x^3 dx)
x⁻ = 1/64 (3 x^4 / 4) from 0 to 4
x⁻ = 1/64 (192) = 3
y⁻ = 1/A (∫ (y dA))
y⁻ = 1/64 (∫ (3x^2 (3x^2 dx)))
y⁻ = 1/64 (∫ (9x^4 dx)
y⁻ = 1/64 (9x^5 / 5) from 0 to 4
y⁻ = 1/64 (9216/5) = 144/5
The centroid of the curve is found at (3, 144/5).
8/12 in its simplest form is 1/3 you can get this by dividing the numerator and denominator by 4 and then by 2
Expanding the given expressions using Foil:
1)(–7x + 4)(–7x + 4) =
2) (–7x + 4)(4 – 7x)=
3)(–7x + 4)(–7x – 4)=
=
4)(–7x + 4)(7x – 4)=
The third option that is (–7x + 4)(–7x – 4) is difference of two squares.
You would have to do 6x2= 12 so it’s 12 outcomes
Answer: i don’t know you can search it up
Step-by-step explanation:
