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3 years ago

Solve ABC triangle if b=15, c=13, and A=50 Emergency question!! Please help right now!!

Mathematics

1 answer:

PolarNik [594]3 years ago

5 0

145 my answer jajanansnananajajaksk. Snsnajnasnsnsnsn s sksksks

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Solve: x to the 3rd power equals 1 over 8

kari74 [83]

X should be 1/2
The way I solved this was by viewing 1/8. I grabbed 8 from the equation and did 8^(1/3) which got me 2. In addition both 1/8 and 1/2^3 in decimal form are both 0.125

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3 years ago

Graph the line with slope 1 passing through the point (-5,2).

Mars2501 [29]

Answer:

(-5,2) (-7,0)

Step-by-step explanation:

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3 years ago

6 program in 2 hours and 18 minutes which rate can he use

nadya68 [22]

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3 years ago

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Plz help me well mark brainliest if correct!!...

valina [46]

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You should stick with option D

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3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

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3 years ago