All categories

3 years ago

Which shapes have at least one pair of parallel sides?

1 answer:

3 0

Parallelograms and trapezoids always do.

(Note: "Parallelograms" includes rectangles, squares, and rhombussesses.)

Any polygon with more than 4 sides <u>can</u> have at least one pair of parallel sides,
but it's not guaranteed.

You might be interested in

The shortest distance from the center of a circle to a line tha is tangent to a circle is

dsp73

Congruent? prob. not

5 0

3 years ago

Help please i don’t understand

Monica [59]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Triangles are similar ,

Thus :

$\frac{9}{3} = \frac{6}{x} \\$

$3 = \frac{6}{x} \\$

$\frac{6}{x} = 3 \\$

Inverse both sides

$\frac{x}{6} = \frac{1}{3} \\$

Multiply sides by 6

$6 \times \frac{x}{6} = 6 \times \frac{1}{3} \\$

$x = 2 \times 3 \times \frac{1}{3} \\$

$x = 2$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

7 0

2 years ago

The population of current statistics students has ages with mean mu and standard deviation sigma. samples of statistics students

hram777 [196]

Answer: The central limit theorem tells us that when random samples are chosen the results tend to approach a normal distribution.

The basic idea is that the more random samples that you select, the closer you should get to the mean. In most cases, 30 or more samples is regarded as a large enough sample to get close to the mean. Our sample is 48, so we should be close to the mean.

3 0

3 years ago

What effect does the "a" value have on the function f(x)=log(x)

Leni [432]

I would guess they're referring to some general form first<span>f(x)=alog(x−h)+k</span>Where 'h' represents horizontal shifts, 'k' vertical shifts and 'a' stretches the function. "a" will also reflect the function across the x-axis if the value is negative. But NOT across the y-axis. I hope that's the place they wanted to put the a at least

5 0

2 years ago

How many 2-digit numbers are multiples of either 5 or 7?

Svet_ta [14]

Answer:

Step-by-step explanation:

he count of numbers from 1 to n that are divisible by k is integer part of (n/k).

So the numbers from 1 to 99 divisible by 3 is int(99/3) = 33

Those divisible by 5: int(99/5) = 19

From the sum of those two, subtract those divisible by 15 = int(99/15) = 6

That gives you 33+19-6 = 46.

Now subtract the 1 digit numbers: 3, 5, 6, 9, or four of them

46 - 4 = 42 is the answer.

4 0

3 years ago

Read 2 more answers