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Mandarinka [93]
3 years ago
7

Round to the nearest ten thousand 738,424

Mathematics
2 answers:
lesya692 [45]3 years ago
8 0

Answer:

740,000

Step-by-step explanation:

Find the 10,000 place which is 38,000 and since 8is above 5 you round up and it's 740,000.

statuscvo [17]3 years ago
3 0

Answer:

740,000

Step-by-step explanation:

hope this helped!

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54=3q show work and step by step
MaRussiya [10]
Divide 54 by 3 which will get you q=18
7 0
4 years ago
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000000000000000000oowwwwwwwwwwwww
vladimir1956 [14]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
In a class test (+ 5) marks are given for every correct answer and (-3) marks are given for every incorrect answer.
OLEGan [10]

Answer:

a. 4 marks b. 9 questions

Step-by-step explanation:

a) Anu gets 8 correct answer and 12 incorrect answers what is her score?

Since Anu got 8 correct answer and 12 incorrect answers, and + 5 marks is given for every correct answer and (-3) marks are given for every incorrect answer, the total score for correct answers is number of correct answer × marks for correct answer = 8 × (+ 5) = 40.

Also,  the total score for incorrect answers is number of incorrect answer × marks for incorrect answer = 12 × (- 3) = -36.

Anu's total score = total score for correct answers + total score for incorrect answers = 40 + (-36) = 40 - 36 = 4 marks.

So, Anu scored 4 marks.

b) Sam answered all the questions and scored 28 marks though he got 11 correct answers.  How many incorrect answers had he attempted?

Let x be the number of incorrect answers. Since the marks for incorrect answers is -3, then his total score for incorrect answers is -3x.

Since Sam got 11 correct answers and is given + 5 marks for each correct answer, then his total score for correct answers is 11 × (+5) = +55.

Since he gets a total of 28 marks, we have that total score for incorrect answer + total score for correct answer = 28.

So, -3x + 55 = 28

Solving for x, we have

-3x = 28 - 55

-3x = -27

x = -27/-3

x = 9

Since x = 9, Sam attempted 9 incorrect questions.

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6 0
3 years ago
Read 2 more answers
How is this one solved?
Vadim26 [7]

Answer:

  see below

Step-by-step explanation:

This is solved by simplifying each expression and identifying the column heading it matches.

1. (6 x^2/(x^2 - 7 x + 10)) / (2 x)/(x - 5))

= (6 x^2/(x^2 - 7 x + 10)) · (x -5)/(2 x) . . . . invert and multiply

= (6x^2)/(2x) · (x -5)/((x -2)(x -5)) . . . . . . . factor so common factors can cancel

= 3x/(x -2) . . . . matches column 1

__

2. (x - 4) (x + 2)/(x^2 + 5 x + 6) + (-3 x^2 + 24 x - 20)/((x + 3) (4 x - 5))

= (x -4)(x +2)/((x +3)(x +2)) + (-3x^2 +24x -20)/((x +3)(4x -5)) . . . factor

= (x -4)/(x +3) + (-3x^2 +24x -20)/((x +3)(4x -5)) . . . . cancel common factor

= ((x -4)(4x -5) +(-3x^2 +24x -20))/((x +3)(4x -5)) . . . . use common denominator

= (4x^2 -21x +20 -3x^2 +24x -20)/((x +3)(4x -5)) . . . expand product

= (x^2 +3x)/((x +3)(4x -5)) . . . . . . collect terms

= (x)(x +3)/((x +3)(4x -5)) . . . . . . factor numerator

= x/(4x -5) . . . . . . . . . . . . . . . . . . cancel common factor ... matches column 2

__

3. 3 x^2/(x + 3) · (2 x + 6)/(2 x^2 - 4 x)

= 3·2·x·(x +3)/((x +3)(2·x)(x -2)) = 3/(x -2) . . . . matches column 1

__

4. 3 x/(4 x - 5) - 4 x^2/(8 x^2 - 10 x)

= 3x/(4x -5) - 4x^2/(2x(4x -5)) = (3x -2x)/(4x -5) = x/(4x -5) ... matches col 2

__

5. 5 x^2/(x - 2) · (2 x + 6)/(8 x^2 - 4 x) . . . . no match (has a denominator factor of 2x-1 that doesn't cancel any numerator factors)

__

6. -x/(4 x - 5) - 4 x^2/(16 x^2 - 22 x)

In order to match one of the columns, the term on the right must reduce to 2x/(4x-5), which it does not, or must have a denominator factor of x-2, which it also does not. no match.

4 0
3 years ago
Please help, ive been stuck on this question for a while
svetlana [45]

Answer: a

Step-by-step explanation:

The graph has a vertex at x=3, so eliminate d and e.

The graph's vertex is at x=1, so eliminate c.

The graph opens upward, so eliminate b.

8 0
2 years ago
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