We know, density = mass / volume
d = 8 / 25
d = 0.32 g/cm3
In short, Your Answer would be 0.32 g/cm3
Hope this helps!
Answer:
I think it is aluminombecause it just makes sense
<u>Answer:</u> The average atomic mass of element bromine is 80.4104 amu.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
- <u>For _{35}^{79}\textrm{Br}[/tex] isotope:</u>
Mass of
isotope = 78.9183 amu
Percentage abundance of
isotope = 50.69 %
Fractional abundance of
isotope = 0.5069
- <u>For
isotope:</u>
Mass of
isotope = 80.9163 amu
Percentage abundance of
isotope = 49.31 %
Fractional abundance of
isotope = 0.4931
Putting values in equation 1, we get:
![\text{Average atomic mass of Bromine}=[(78.9183\times 0.5069)+(80.9163\times 0.4931)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20Bromine%7D%3D%5B%2878.9183%5Ctimes%200.5069%29%2B%2880.9163%5Ctimes%200.4931%29%5D)

Hence, the average atomic mass of element bromine is 80.4104 amu.
a) (NH4)2SO4 --- 1 mole of it contains 2 moles of N, 8 moles of H, 1 mole of S, and 4 moles of O.
MM = (2 moles N x 14.0 g/mole) + (8 moles H x 1.01 g/mole) + (1 mole S x 32.1 g/mole) + (4 moles O x 16.0 g/mole) = 132 g/mole.
6.60 g (NH4)2SO4 x (1 mole (NH4)2SO4 / 132 g (NH4)2SO4) = 0.0500 moles (NH4)2SO4
b) The molar mass for Ca(OH)2 = 74.0 g/mole, calculated like (NH4)2SO4 above.
4.5 kg Ca(OH)2 x (1000 g / 1 kg) x (1 mole Ca(OH)2 / 74.0 g Ca(OH)2) = 60.8 moles Ca(OH)2
The Andes was the mountain range that formed as a result of plate motion around the Ring of Fire.
Answer: The Andes