Answer:
202 g/mol
Explanation:
Let's consider the neutralization between a generic monoprotic acid and KOH.
HA + KOH → KA + H₂O
The moles of KOH that reacted are:
0.0164 L × 0.08133 mol/L = 1.33 × 10⁻³ mol
The molar ratio of HA to KOH is 1:1. Then, the moles of HA that reacted are 1.33 × 10⁻³ moles.
1.33 × 10⁻³ moles of HA have a mass of 0.2688 g. The molar mass of the acid is:
0.2688 g/1.33 × 10⁻³ mol = 202 g/mol
Fe2O3 + 2Al => Al2O3 + 2Fe↓
reaction of changing.
In this type of reaction one element or group of elements from one substance is changed with a single element.
At STP conditions the volume of 1 mol of any ideal gas will be 22.4L
0.500 mol C3H3 x 22.4L / 1 mol = 11.2 L
For calculating the number of moles of uranium, we can count how many atoms of uranium exist in 1 molecule of the given, and multiply this by the given 8.00 moles.
Carnotite contains (UO2)2, meaning that it has 2 U atoms. Multiplying by 8 gives 16 moles of uranium.
Uranophane contains U2, meaning it has 2 U atoms. Multiplying by 8 gives 16 moles of uranium.
Autunite contains (UO2)2, meaning it has 2 U atoms. Multiplying by 8 also gives 16 moles of uranium.
Therefore, in 8 moles of all 3 compounds given, there are 16 moles of uranium.
Answer: 
Explanation:
Let consider that one mole of diatomic oxygen is used. So, the stoichometric can be modelled by using three variables:
Where 
are the required variables.
Now, three equations are constructed from the number of elements involved (Carbon, Hydrogen and Oxygen):
Carbon
Oxygen
Hydrogen
The coefficients can be found by solving the abovementioned 3 x 3 Linear System:
The whole-number coefficients are determined by multiplying every coefficient by 3, then:
