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0 less than or equal to x less than or equal to 20
Answer:
-1 and 0
Step-by-step explanation:
X ^4+x = 0;
x*(x^3+1)=0;
x*[(x^3-x)+(x+1)]=0;
x*[x(x-1)(x+1)+(x+1)]=0;
x*(x+1)(x^2-x+1)=0;
Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0
x=0 or -1
We need to solve for x by completing the square of the given mathematical expression (x+7)(x-9) = 25.
First, we need to perform multiplication of (x+7) and (x-9) such as the expression become:
(x+7) (x-9) = 25
x² -9x +7x -63 = 25
x² - 2x = 25 + 63
Then perform addition of constant values 25 and 63
x² - 2x =88
Add +1 in both sides to complete the expression such as:
x² - 2x +1 = 88 +1
(x-1)(x-1) = 89
(x-1)² = 89
We see that (x-1) is a perfect square, we can now solve for the value of x such as:
(x-1) = +-√89
x1 = +√89 + 1
x1 = 10.4
x2 = -√89 +1
x2 = -8.4
The answers are 10.4 and -8.4.
Answer:
im not too sure but i think the answer is c
Step-by-step explanation:
