Answer:
mark me
Step-by-step explanation:
x+y=3
x=3-y
putting the value of x
in this
x²+y²=5
(3-y) ²+y²=5
9-6y+y²+y²=5
2y²-6y+9-5=0
2y²-6y+4=0
2y²-4y-2y+4=0
2y(y-2)-2(y-2)=0
(2y-2) (y-2) =0
2y-2=0 or y-2=0
y=1 or y=2
so x=2 or 1
so x×y=2×1 or 1×2=2
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
-1/12 - (-11/12) would change into -1/12 + 11/12 because a double negative (bold print) would become a positive. The answer to the new problem would be 10/12 or 5/6 (depending on if it says to simplify).
Answer:

Step-by-step explanation:
y = 3x + 14
y = x
.
x = 3x + 14
3x - x = -14
2x = -14

x = -7
.
y = x
y = -7

- subtract the 12 from both sides so that it becomes the last constant term in the quadratic equation which should now equal 0.
- take the 4x
- half the coefficient of 4 (2)
- square it (4)
- add it to the equation (+4)
- subtract it from the equation (-4)
- factorise the square (x+2)^2 expands to (x^2 + 4x + 2) as {a+b}^2={a^2 + ab + ba + b^2}
- now the equation is in turning point form.
- to find x, add 16 and square root 16 and (x+2)
- subtract 2 from positive or negative 4 (as -4^2 and 4^2 both equal 16).
- This should give you two values for x, -6 and 2.
I really hope that this helped :)
A line always has a general equation of y = mx + b where m is the slope of the line and b is the y-intercept. Slope is the rise of one point per run and the y-intercept is the value of y when x is 0. So, the equation should be,
y = (rise/run) x - 4