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3 years ago

What is sum of the vectors, LeftAngleBracket 4, negative 5 RightAngleBracket and LeftAngleBracket 10, 2 RightAngleBracket?

Mathematics

2 answers:

mylen [45]3 years ago

6 0

Answer:

14,-3

Step-by-step explanation:

pentagon [3]3 years ago

3 0

Answer:

Step-by-step explanation:

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

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natita [175]

Answer:

Step-by-step explanation:

-4,5

6 0

1 year ago

Read 2 more answers

What is the product?

densk [106]

The right answer is of option C

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment

5 0

3 years ago

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Help ASAP. Can somebody please tell if this is the correct answer. If not put the correct answer And help me if I need to graph

RSB [31]

Answer: closed circle pointing to the right.

Step-by-step explanation:

Given that the inequality equation is

6 ( 2 - 3y ) < = 36

Open the bracket

12 - 18y < = 36

Collect the like terms

- 18y < = 36 - 12

Make y the subject of formula

The inequality sign will change the moment you multiply or divide both sides by negative numbers

Y > = - 24/18

Y > = - 4/3

That is y is greater than or equal to negative 4/3

Graphing the above inequality,

The point will be between -2 and -1. And it will be closer to -1.

The arrow will point to the right and it will be a closed circle since it is greater than or equal to.

8 0

3 years ago

Please help ASAP is this correct?

emmasim [6.3K]

Answer:

yess that is correct

Step-by-step explanation:

18<27

7 0

3 years ago

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