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3 years ago

12

I need answers to these problems

1 answer:

Nataly [62]3 years ago

4 0

1. Cost = room rental + transportation
Let units of cost be "dollars" and let "n" represent the number of people going on the field trip.
.. cost = 637 +18n
.. revenue = 105 +25n

2. You want to find "n" so that revenue matches cost.
.. revenue = cost
.. 105 +25n = 637 +18n
.. 7n = 532
.. n = 76
76 people need to make the trip to break even

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Q(x)= 1/2x - 3; q(x) =-4. Find the value of x

Lelu [443]

Answer:

$q(x) =-5$

Step-by-step explanation:

I am solving this using Function Notation.

We are given:

$q(x)= \frac{1}{2}x - 3$

While we are to find:

$q(x) =-4$

In Function Notation, replace all the " $x$ " you see with the value you are given.

So, in this case,

$q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}x - 3$

Would become

$q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}(-4) - 3$

Now we can solve.

$\frac{1}{2}(-4) - 3$

Use PEMDAS; Parenthesis first;

$\frac{1}{2}(-\frac{4}{1})$

Cross divide: 1 cancels 1, -4 ÷ 2 = -2

Hence, we are left with

$(-2) - 3$

$-5$

Therefore, the value of x is -5

8 0

2 years ago

How many 1/16 inches are in one inch?

Dafna11 [192]

The answer is 16 inches are in 1/16 inches

8 0

2 years ago

Evaluate (c − b)2 + a2 for a = –5, b = –2, and c = –4.

taurus [48]

(c - b)² + a²

a = -5

b = -2

c = -4

(-4 - (-2))² + (-5)²

(-4 + 2)² + (-5)²

(-2)² + (-5)²

4 + 25

29

3 0

3 years ago

The drying times for a certain type of cement are normally distributed with a standard deviation of 30 minutes. A researcher wis

IceJOKER [234]

Answer:

h. 36

Step-by-step explanation:

For a 68.26% confidence, z = 1.0.

Standard deviation (s) = 30 minutes

The sample size needed to assure that the sample mean does not differ from the true mean by more than 5 minutes is given by:

$5\geq z*\frac{s}{\sqrt n}\\\sqrt n\geq 1*\frac{30}{5}\\n\geq 36$

The sample size needed is 36.

5 0

3 years ago

Dave and Sandy Hartranft are frequent flyers with a particular airline. They often fly from City A to City B, a distance of 756

horsena [70]

Answer:

Plane = 441 mi/h; wind = 63 mi/h

Step-by-step explanation:

distance = rate × time

Let p = the plane's speed in still air

and w = the wind speed . Then,

p + w = speed with wind

p - w = speed against wind

We have two conditions:

(1) 756 = (p - w) × 2

(2) 756 = (p + w) × 1.5

Distribute the constants (3) 756 = 2p - 2w

(4) 756 = 1.5p + 1.5 w

Multiply Equation (3) by 3 (5) 2268 = 6p - 6w

Multiply Equation (4) by 4 (6) 3024 = 6p + 6w

Add Equations (5) and (6) 5292 = 12p

Divide each side by 12 (7) p = 441 mi/h

Substitute (7) into Equation(3) 756 = 882 - 2w

Add 2w to each side 2w + 756 = 882

Subtract 756 from each side 2w = 126

Divide each side by 2 w = 63 mph

The plane's speed in still air is 441 mi/h.

The wind speed is 63 mph.

Check:

(1) 756 = (441 - 63) × 2 (2) 756 = (441 + 63) × 1.5

756 = 378 × 2 756 = 504 × 1.5

756 = 756 756 = 756

8 0

3 years ago