Answer:
15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Step-by-step explanation:
We are to find the derivative of the questions pointed out.
15) K(t) = 5(5^(t)) - 2(3^(t))
Using implicit differentiation, we have;
K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P(w) = 2e^(w) - (2^(w))/5
P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)
Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)
Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Answer:
181.46 cm
Step-by-step explanation:
28.47 * 637.47 / 100 = 181.46
I am going to assume these are points across the same line. (line segments)
If so, then jk + kl = jl
If jk is 6x and kl is 3x, we can solve for x.
6x + 3x = 27 (note we subbed 27 in for jl)
9x = 27 (divide both sides by 9 to leave on x on the left)
x = 3
CHECK! sub 3 in for x in the original problem.
6 (3) + 3 (3) = 27
18 + 9 = 27
Yes! It checks. x = 3
In down angle there is 26 there is not 28 so 28×2 =56
Step-by-step explanation:
we need angle on the left side 2
