I think 3 because if u divide 207 by 69 you get 3
Answer:
B.
Step-by-step explanation:
Total coins = 11 ( 3 + 4 + 4 = 11).
The probability of picking a nickel first = 3/11 ( 4 nickels out of 11 total).
The probability of picking a dime second = 4/10 = 2/5 ( 3 dimes out of 10 coins left).
The probability of picking the third coin as a quarter = 4/9 ( 3 quarters out of 9 coins left).
The probability of picking all three in that order = 3/11 x 2/5 x 4/9 = 8/165
M(x)=−(x−5) 2 +25m, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 5, right parenthesis, squ
Aleksandr [31]
Answer:
25
Step-by-step explanation:
Given the function that represents the amount of mosquitoes as;
M(x) = -(x-5)² + 25
To get the maximum mosquitoes possible, we need to first find x;
At the maximum dM/dx = 0
dM//dx = -2(x-5)
0 = -2(x-5)
-2(x-5) = 0
-2x + 10 = 0
-2x = -10
x = 10/2
x = 5
Substitute x = 5 into the function;
M(5) = −(5−5)² +25
M(5) = 0+25
M(5) = 25
Hence the maximum number of mosquitoes is 25
Answer:
x = 60°
Step-by-step explanation:
AOB Center: O AB: diameter
arc ADB = 180°
arc DB = 180 - arc AD = 80°
x = 1/2 x ( arc DB + arc AC) = 1/2 x (80 + 40) = 60°
