All categories

2 years ago

Show work and ill give credit

Mathematics

1 answer:

FromTheMoon [43]2 years ago

5 0

9514 1404 393

Answer:

Step-by-step explanation:

To solve the inequality, we can do the following.

4.55g + 8.50 ≤ 35 . . . given

4.55g ≤ 26.50 . . . . . . subtract 8.50 from both sides

g ≤ 5.82... . . . . . . . . . . divide both sides by 4.55

The number of games must be an integer value, so the maximum number of games they can bowl is 5.

You might be interested in

A forest covers 66,000 acres. A survey finds that 0.2% of the forest is old-growth trees. How many acres of old-growth trees are

marshall27 [118]

Answer:

132

Step-by-step explanation:

easy 66,000 * .002

6 0

2 years ago

Plsss Help!!! Will mark brainiest!! Due soon!!

Vladimir [108]

Answer:

√41

Step-by-step explanation:

Top is the formula, and the bottom would be how to plug in the points.

4 0

2 years ago

Read 2 more answers

Jack Wilson bought a tool chest and tools on the installment plan for a total cost $1600. He paid $200 down and the rest in mont

Sergio039 [100]

Answer:

25 months

Step-by-step explanation:

quick math

3 0

2 years ago

Plz help me with this binary division whith full process/explanation 1001010 ÷ 101

aivan3 [116]

Answer:

Step-by-step explanation:

Its like doing a long division with base 10 numbers:

1110 <----------- Quotient

101)1001010

101

1000

101

111

101

100

So the answer is 1110 remainder 100.

We can confirm this by converting to decimal numbers

1001010 = 74 and 101 = 5.

74 / 5 = 14 remainder 4.

3 0

2 years ago

Find the term indecent of x in the expansion of (x^2-1/x)^6

Mars2501 [29]

By the binomial theorem,

$\displaystyle \left(x^2-\frac1x\right)^6 = \sum_{k=0}^6 \binom 6k (x^2)^{6-k} \left(-\frac1x\right)^k = \sum_{k=0}^6 \binom 6k (-1)^k x^{12-3k}$

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0 ===> 3k = 12 ===> k = 4

which corresponds to the constant coefficient

$\dbinom 64 (-1)^4 = \dfrac{6!}{4!(6-4)!} = \boxed{15}$

3 0

2 years ago