I must assume that you meant t=1 (not t=?1). If t=1, here's what we'd do:
1. Find the x and y values corresponding to t=1. They are:
x=(1)^7+1=2 and y=(1)^8+1=2. (Please note: write t^8 instead of t8, and write t^7 instead of t7.)
2. The slope of the tangent line to the graph is
dy/dt 8t^7+1
dy/dx = ---------- = ---------------- with 1 substituted for t
dx/dt 7t^6
Thus, dy/dx (at t=1) = 9/7
3. Now we have both a point (2,2) on the graph and the slope of the tangent line to the curve at that point: 9/7
4. The tangent line to the curve at (2,2) is found by using the point-slope formula:
y-y1 = m(x-x1)
which comes out to y-2 = 9/7(x-2), or 7y-14 = 9(x-2). You could, if you wished, simplify this result further (e. g., by solving for y in terms of x).
Answer:
$23,700
Step-by-step explanation:
The compound interest formula can be helpful for this. Fill in the given values and solve for the unknown.
FV = P(1 +r/n)^(nt)
where r is the annual interest rate, n is the number of times interest is compounded in a year, t is the number of years, P is the amount invested, and FV is the future value of that investment.
$27,000 = P(1 +0.022/365)^(365·6) = 1.1411037P
P ≈ $23,700
This ordered pair lands on the the Y axis
Answer:
1. Multiply the value of the first variable by one of the original equations to solve for the second variable.
2. Solve for one of the variables.
3. Substitute the value of the known variable into one of the original equations to solve for the unknown variable.
Step-by-step explanation:
