Distribute5x (3x + 7)

Hannah claims that people who live in southern states spend 9 hours more per week outside than do people in northern states. She

vova2212 [387]

Answer:

b. Hannah is likely to be incorrect because 9 is not contained in the interval.

Step-by-step explanation:

Hello!

Hannah estimated per CI the difference between the average time that people spend outside in southern states and the average time people spend outside in northern states.

The CI is a method of estimation of population parameters that propose a range of possible values for them. The confidence level you use to construct the interval can be interpreted as, if you were to calculate 100 confidence interval, you'd expect that 99 of them will contain the true value of the parameter of interest.

In this example, the 99%CI resulted [0.4;8.0]hs

Meaning that with a 99% confidence level you'd expect the value of the difference between the average time people from southern states spend outside than the average time people from northern states spend outside is included in the interval [0.4;8.0]hs.

Now, she claims that people living in southern states spend 9 more hours outside than people living in northern states, symbolized μ₁ - μ₂ > 9

Keep in mind that if you were to test her claim, the resulting hypothesis test would be one-tailed

H₀: μ₁ - μ₂ ≤ 9

H₁: μ₁ - μ₂ > 9

And that the calculated Ci is tow-tailed, so it is not valid to use it to decide over the hypotheses pair. This said, considering that the calculated interval doesn't contain 9, it is most likely that Hannah's claim is incorrect.

I hope this helps!

6 0

3 years ago

Traeq pays 35.34 for 3.1 pounds of salmon. What is the price per pound of salmon

Morgarella [4.7K]

$11.40 because you just divide 35.34 by 3.1

3 0

3 years ago

PLEASE HELP I AM DESPERATE!!!

Vilka [71]

Answer:

Statements:

m<b = 180 - m<a

m<c = 180 - m<d

m<b = m<c

180 - m<a = 180 - m<d

Reasons:

The measure of m<b is the angle of a straight line subtracted with m<a. The measure of m<c is the angle of a straight line subtracted with m<d. If m<a and m<d are equal, m<b and m<c are equal.

Step-by-step explanation:

We know, m<a = m<d

So, we need to prove m< b = m<c

Let's start by defining what b and c is

m<b + m<a = 180 This is because a straight line is 180 degrees

m<b = 180 - m<a

m<c + m<d = 180

m<c = 180 - m<d

With this, we can substitute in proof

m<b = m< c

180 - m<a = 180 - m<d

180 - m<a = 180 - m<a

Your welcome for the answer. Tell me if you have any questions in the comments section of this answer! If you could mark this answer as the brainliest, I would greatly appreciate it!

4 0

3 years ago

What is the equation of the line with a slope of 1/4 and a y-intercept of 2?

ELEN [110]

Equation of the line in slope intercept form is

y = 1/4 * x + 5. Slope is 1/4. Intercept is 5.

If x= 4, y = (1/4)*4 + 5 = 6.

The point (4,6) lies on the line.

Equation of the line in point slope form is

(y - y1)= m * (x - x1) where m is slope & (x1,y1) is point on the line.

Substituting slope m= 1/4 & point (4,6),

Equation of the line in point-slope form is:

(y - 6) = 1/4 * (x - 4).

Sanjay C.

6 0

3 years ago

Read 2 more answers

Verify that y1(t) = 1 and y2(t) = t ^1/2 are solutions of the differential equation:

Papessa [141]

Answer: it is verified that:

* y1 and y2 are solutions to the differential equation,

* c1 + c2t^(1/2) is not a solution.

Step-by-step explanation:

Given the differential equation

yy'' + (y')² = 0

To verify that y1 solutions to the DE, differentiate y1 twice and substitute the values of y1'' for y'', y1' for y', and y1 for y into the DE. If it is equal to 0, then it is a solution. Do this for y2 as well.

Now,

y1 = 1

y1' = 0

y'' = 0

So,

y1y1'' + (y1')² = (1)(0) + (0)² = 0

Hence, y1 is a solution.

y2 = t^(1/2)

y2' = (1/2)t^(-1/2)

y2'' = (-1/4)t^(-3/2)

So,

y2y2'' + (y2')² = t^(1/2)×(-1/4)t^(-3/2) + [(1/2)t^(-1/2)]² = (-1/4)t^(-1) + (1/4)t^(-1) = 0

Hence, y2 is a solution.

Now, for some nonzero constants, c1 and c2, suppose c1 + c2t^(1/2) is a solution, then y = c1 + c2t^(1/2) satisfies the differential equation.

Let us differentiate this twice, and verify if it satisfies the differential equation.

y = c1 + c2t^(1/2)

y' = (1/2)c2t^(-1/2)

y'' = (-1/4)c2t(-3/2)

yy'' + (y')² = [c1 + c2t^(1/2)][(-1/4)c2t(-3/2)] + [(1/2)c2t^(-1/2)]²

= (-1/4)c1c2t(-3/2) + (-1/4)(c2)²t(-3/2) + (1/4)(c2)²t^(-1)

= (-1/4)c1c2t(-3/2)

≠ 0

This clearly doesn't satisfy the differential equation, hence, it is not a solution.

6 0

3 years ago