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allochka39001 [22]
2 years ago
15

Avery bought stock in a company two years ago that was worth x dollars. During the first year that she owned the stock, it incre

ased by 40%. During the second year the value of the stock decreased by 10%.
Mathematics
1 answer:
Otrada [13]2 years ago
4 0

Answer:

The value of the stock can be found by: x × 1.26.

Step-by-step explanation:

The value of the stock in year one can be found by multiplying x by 1.4. This will represent a 40% increase in value. The following year, the stock decreases in value by 10%; this is represented by multiplication by 0.9. For example, if the value of the stock was $5:

5 × 1.4 = 7                    (A 40% increase in value)

(5 × 1.4) * 0.90 = 6.3   (A further 10% decrease in value)

Rather than writing out the long version, we can simplfify by multiplying 1.4 by 0.9 to get 1.26 .We can also replace 5 with x to get a more general equation.

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Step-by-step explanation:

Move the decimal place from 2.375 to the back of the number so it should look like this, 2375.

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Sec squared 55 - tan squared 55
sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55  = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}

And,

\tan \theta=\frac{\text { perpendicular }}{\text { base }}

where Ө is the angle

Substituting the values

\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}

Solving,

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}

According to Pythagoras theorem,

\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}

Putting this in the equation;

squared 55 - tan squared 55 =

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1

Therefore, sec squared 55 – tan squared 55 = 1

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Answer:

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3 years ago
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