Question

Reggie and Alvin and Jose are member of a relay running team Reggie finish his leg of the race 2.4 five seconds faster than Alvin and 3.8 one seconds slower than Jose. If Reggie time for his leg of the race was 57.12 seconds what was the total time for the team show your work

Answer 1

The time taken by Reggie for his leg of the race is 57.12 seconds.

Alvin is 2.45 seconds slower than Reggie. Therefore, time taken by Alvin for his leg of the race is:

$57.12+2.45= 59.57$ seconds

We also know that Jose is faster than Reggie by 3.81 seconds. Therefore, time taken by Jose for his leg of the race will be:

$57.12-3.81=53.31$ seconds

Thus, the total time for the team will be the sum of the times taken by Reggie, Alvin and Jose for their respective legs.

Therefore, total time for the team is: $57.12+59.57+53.31 =170.02$ seconds