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cestrela7 [59]
3 years ago
9

Question 1 (5 points)

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Step-by-step explanation:

Sorry I had to crop it but basically since it's 140 barrels per every 1 hour then the equation is 140 multiplied by the number of hours. So 0 hours is 0 barrels, 1 hour is 140, 2 hours is 280, etc...

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How to solve 2.2z=6.8
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Answer:

3.09

Step-by-step explanation:

divide 2.2 by 6.8 then z would equal 3.09

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Please help, this is from ANNOYING Khan Academy.
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-20

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length x width x height = volume

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If your car can travel 20 miles on 1 gallon of fuel how many litres were used to travel 130 miles? Step by step
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3 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
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